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Q. A particle of mass m oscillates with simple harmonic motion between points $x_{1}$ and $x_{2}$ the equilibrium position being $O.$ Its potential energy is plotted. It will be as given below in the graph

NTA AbhyasNTA Abhyas 2020

Solution:

Potential energy of particle performing SHM is given by: $PE=\frac{1}{2}m\omega ^{2}y^{2}$ i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.