A particle of mass 200 g is dropped from a height of 50 m and another particle of mass 100 g is simultaneously projected up from the ground along the same lime, with a speed of 100 m / s. the acceleration of the centre of mass after 1 s is

Question

A particle of mass 200 g is dropped from a height of 50 m and another particle of mass 100 g is simultaneously projected up from the ground along the same lime, with a speed of 100 m / s. the acceleration of the centre of mass after 1 s is (A) 10 m / s 2 (B) (10/3) m / s 2 (C) 0 (D) None of these.

Tardigrade Admin · Accepted Answer

As only force of gravity acts, so acceleration of centre of mass will be g=10 m / s 2

Q. A particle of mass $200 g$ is dropped from a height of $50 m$ and another particle of mass $100 g$ is simultaneously projected up from the ground along the same lime, with a speed of $100 m / s$ . the acceleration of the centre of mass after $1 s$ is

$10 m / s^{2}$

$\frac{10}{3} m / s^{2}$

0

None of these.

As only force of gravity acts, so acceleration of centre of mass will be $g = 10 m / s^{2}$

Q. A particle of mass 200g is dropped from a height of 50m and another particle of mass 100g is simultaneously projected up from the ground along the same lime, with a speed of 100m/s. the acceleration of the centre of mass after 1s is

10m/s2

310​m/s2

0

None of these.

As only force of gravity acts, so acceleration of centre of mass will be g=10m/s2

Q. A particle of mass $200 g$ is dropped from a height of $50 m$ and another particle of mass $100 g$ is simultaneously projected up from the ground along the same lime, with a speed of $100 m / s$ . the acceleration of the centre of mass after $1 s$ is

$10 m / s^{2}$

$\frac{10}{3} m / s^{2}$

As only force of gravity acts, so acceleration of centre of mass will be $g = 10 m / s^{2}$