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Q. A particle of mass $200\, g$ is dropped from a height of $50 \,m$ and another particle of mass $100 \,g$ is simultaneously projected up from the ground along the same lime, with a speed of $100 \,m / s$. the acceleration of the centre of mass after $1\, s$ is

System of Particles and Rotational Motion

Solution:

As only force of gravity acts, so acceleration of centre of mass will be $g=10\, m / s ^{2}$