A particle of mass 10 kg is moving in a straight line. If its displacement is given by x =( t3-2t-10) then the force acting on it at the end of 4 s is

Question

A particle of mass 10 kg is moving in a straight line. If its displacement is given by x =( t3-2t-10) then the force acting on it at the end of 4 s is (A) 1200 N (B) 240 N (C) 300N (D) 24 N

Tardigrade Admin · Accepted Answer

∴ : :: upsilon = (dx/dt) = 3t2 - 2 a = (dv/dx) = (3 × 2 )t = 6t = 6 × 4 = 24 m s-2 Force = m × a = 10 × 24 = 240 N

Q. A particle of mass 10 kg is moving in a straight line. If its displacement is given by $x = (t^{3} - 2 t - 10)$ then the force acting on it at the end of 4 s is

1200 N

240 N

300N

24 N

$∴ υ = \frac{d x}{d t} = 3 t^{2} - 2$
$a = \frac{d v}{d x} = (3 \times 2) t = 6 t = 6 \times 4 = 24 m s^{- 2}$
Force = $m \times a = 10 \times 24$
$= 240 N$

Q. A particle of mass 10 kg is moving in a straight line. If its displacement is given by x=(t3−2t−10) then the force acting on it at the end of 4 s is