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  4. A particle of mass 10 kg is moving in a straight line. If its displacement is given by x =( t3-2t-10) then the force acting on it at the end of 4 s is

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Q. A particle of mass 10 kg is moving in a straight line. If its displacement is given by $x\,=(\,t^3-2t-10)$ then the force acting on it at the end of 4 s is

Laws of Motion

Solution:

$\therefore \:\:\: \upsilon = \frac{dx}{dt} = 3t^2 - 2$
$a = \frac{dv}{dx} = (3 \times 2 )t = 6t = 6 \times 4 = 24 \, m \, s^{-2}$
Force = $m \times a = 10 \times 24 $
$= 240\,N$