A particle of charge per unit mass α is released from origin with a velocity barv=v0 hati in a uniform magnetic field barB=-B0 hatk. If the particle passes through (0, y, 0) then y is equal to

Question

A particle of charge per unit mass α is released from origin with a velocity barv=v0 hati in a uniform magnetic field barB=-B0 hatk. If the particle passes through (0, y, 0) then y is equal to (A) -(2 v0/B0 α) (B) (v0/B0 α) (C) (2 v0/B0 α) (D) -(v0/B0 α)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a0e76e341f7a594d69274ced0874ae87-.png" /> (q/m)=α y=2 R=2((m v/q B))=(2 v0/α B0)

Q. A particle of charge per unit mass $α$ is released from origin with a velocity $\overset{v}{ˉ} = v_{0} \hat{i}$ in a uniform magnetic field $\overset{ˉ}{B} = - B_{0} \hat{k}$ . If the particle passes through $(0, y, 0)$ then $y$ is equal to

$- \frac{2 v _{0}}{B _{0} α}$

$\frac{v _{0}}{B _{0} α}$

$\frac{2 v _{0}}{B _{0} α}$

$- \frac{v _{0}}{B _{0} α}$

$\frac{q}{m} = α$
$y = 2 R = 2 (\frac{m v}{qB}) = \frac{2 v _{0}}{α B _{0}}$

Q. A particle of charge per unit mass α is released from origin with a velocity vˉ=v0​i^ in a uniform magnetic field Bˉ=−B0​k^. If the particle passes through (0,y,0) then y is equal to

−B0​α2v0​​

B0​αv0​​

B0​α2v0​​

−B0​αv0​​