Question

A particle of charge per unit mass $\alpha$ is released from origin with a velocity $\bar{v}=v_{0} \hat{i}$ in a uniform magnetic field $\bar{B}=-B_{0} \hat{k}$. If the particle passes through $(0, y, 0)$ then $y$ is equal to

• A. $-\frac{2 v_{0}}{B_{0} \alpha}$
• B. $\frac{v_{0}}{B_{0} \alpha}$
• C. $\frac{2 v_{0}}{B_{0} \alpha}$
• D. $-\frac{v_{0}}{B_{0} \alpha}$

Answer 1

Answer: (C)

$\frac{q}{m}=\alpha$
$y=2 R=2\left(\frac{m v}{q B}\right)=\frac{2 v_{0}}{\alpha B_{0}}$