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Tardigrade
Question
Physics
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2π s. The acceleration of the particle is
Q. A particle moves in a circle of radius 5 cm with constant speed and time period
0.2
π
s
.
The acceleration of the particle is
1896
235
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A
25
m
/
s
2
B
36
m
/
s
2
C
5
m
/
s
2
D
15
m
/
s
2
Solution:
r
=
5
c
m
=
5
×
10
−
2
m
and
T
=
0.2
π
s
We know that acceleration
a
=
r
ω
2
=
T
2
4
π
2
r
=
(
0.2
π
)
2
4
×
π
2
×
5
×
10
−
2
=
5
m
s
−
2