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  4. A particle moves in a circle of radius 5 cm with constant speed and time period 0.2π s. The acceleration of the particle is

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Q. A particle moves in a circle of radius 5 cm with constant speed and time period $ 0.2\pi s. $ The acceleration of the particle is

VMMC MedicalVMMC Medical 2012

Solution:

$ r=5\,cm=5\times {{10}^{-2}}m $ and $ T=0.2\,\pi s $ We know that acceleration $ a=r{{\omega }^{2}} $ $ =\frac{4{{\pi }^{2}}}{{{T}^{2}}}r $ $ =\frac{4\times {{\pi }^{2}}\times 5\times {{10}^{-2}}}{{{(0.2\pi )}^{2}}}=5\,m{{s}^{-2}} $