A particle moves along X -axis in such a way that its x -coordinate varies with time t according to the equation x=(6-4 t+6 t2) metre. The velocity of the particle will vary with time according to the graph

Question

A particle moves along X -axis in such a way that its x -coordinate varies with time t according to the equation x=(6-4 t+6 t2) metre. The velocity of the particle will vary with time according to the graph (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

x=6-4 t+6 t2, v=(a x/d t)=-4+12 t So v-t graph is a straight line and at t=0, v=-4 ms -1

Q. A particle moves along $X$ -axis in such a way that its $x$ -coordinate varies with time $t$ according to the equation $x = (6 - 4 t + 6 t^{2})$ metre. The velocity of the particle will vary with time according to the graph

$x = 6 - 4 t + 6 t^{2}, < b r / >< b r / > v = \frac{a x}{d t} = - 4 + 12 t$
So $v - t$ graph is a straight line and at $t = 0, v = - 4 m s^{- 1}$

Q. A particle moves along X -axis in such a way that its x -coordinate varies with time t according to the equation x=(6−4t+6t2) metre. The velocity of the particle will vary with time according to the graph

x=6−4t+6t2,<br/><br/>v=dtax​=−4+12t So v−t graph is a straight line and at t=0,v=−4ms−1

Q. A particle moves along $X$ -axis in such a way that its $x$ -coordinate varies with time $t$ according to the equation $x = (6 - 4 t + 6 t^{2})$ metre. The velocity of the particle will vary with time according to the graph

$x = 6 - 4 t + 6 t^{2}, < b r / >< b r / > v = \frac{a x}{d t} = - 4 + 12 t$
So $v - t$ graph is a straight line and at $t = 0, v = - 4 m s^{- 1}$