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Q. A particle moves along $X$ -axis in such a way that its $x$ -coordinate varies with time $t$ according to the equation $x=\left(6-4 t+6 t^{2}\right)$ metre. The velocity of the particle will vary with time according to the graph

Motion in a Straight Line

Solution:

$x=6-4 t+6 t^{2},
v=\frac{a x}{d t}=-4+12 t$
So $v-t$ graph is a straight line and at $t=0, v=-4 ms ^{-1}$