A particle moves along with x-axis. The position x of particle with respect to time t from origin given by x=b0+b1t+b2t2 . The acceleration of particle is

Question

A particle moves along with x-axis. The position x of particle with respect to time t from origin given by x=b0+b1t+b2t2 . The acceleration of particle is (A)  b0  (B)  b1  (C)  b2  (D)  2b2

Tardigrade Admin · Accepted Answer

Distance, x=b0+b1t+b2t2 Velocity v=( (dx/dt) ) =b1+2b2t Acceleration, α =(d2x/dt2)=2b2

Q. A particle moves along with x-axis. The position $x$ of particle with respect to time t from origin given by $x = b_{0} + b_{1} t + b_{2} t_{2}$ . The acceleration of particle is

$b_{0}$

$b_{1}$

$b_{2}$

$2 b_{2}$

Distance, $x = b_{0} + b_{1} t + b_{2} t^{2}$ Velocity $v = (\frac{d x}{d t})$
$= b_{1} + 2 b_{2} t$
Acceleration, $α = \frac{d ^{2} x}{d t ^{2}} = 2 b_{2}$

Q. A particle moves along with x-axis. The position x of particle with respect to time t from origin given by x=b0​+b1​t+b2​t2​ . The acceleration of particle is

b0​

b1​

b2​

2b2​