Question

A particle moves along with x-axis. The position $ x $ of particle with respect to time t from origin given by $ x={{b}_{0}}+{{b}_{1}}t+{{b}_{2}}{{t}_{2}} $ . The acceleration of particle is

• A. $ {{b}_{0}} $
• B. $ {{b}_{1}} $
• C. $ {{b}_{2}} $
• D. $ 2{{b}_{2}} $

Answer 1

Answer: (A)

Distance, $ x={{b}_{0}}+{{b}_{1}}t+{{b}_{2}}{{t}^{2}} $ Velocity $ v=\left( \frac{dx}{dt} \right) $
$ ={{b}_{1}}+2{{b}_{2}}t $
Acceleration, $ \alpha =\frac{{{d}^{2}}x}{d{{t}^{2}}}=2{{b}_{2}} $