A particle is moving eastwards with a speed of 6 m / s. After 6 s, the particle is found to be moving with same speed in a direction 60° north of east. The magnitude of average acceleration in this interval of time is

Question

A particle is moving eastwards with a speed of 6 m / s. After 6 s, the particle is found to be moving with same speed in a direction 60° north of east. The magnitude of average acceleration in this interval of time is (A) 6 m / s 2 (B) 3 m / s 2 (C) 1 m / s 2 (D) Zero

Tardigrade Admin · Accepted Answer

|Δ vecv|=2 v sin (θ/2)=2 v sin ((60/2))=2 v sin 30°=v |Δ vecv|=6 ms -1 Δ t=6 s so, a av =(6/6)=1 ms -2

Q. A particle is moving eastwards with a speed of $6 m / s$ . After $6 s$ , the particle is found to be moving with same speed in a direction $6 0^{\circ}$ north of east. The magnitude of average acceleration in this interval of time is

$6 m / s^{2}$

$3 m / s^{2}$

$1 m / s^{2}$

Zero

$∣Δ v ∣ = 2 v sin \frac{θ}{2} = 2 v sin (\frac{60}{2}) = 2 v sin 3 0^{\circ} = v$
$∣Δ v ∣ = 6 m s^{- 1}$
$Δ t = 6 s$
so, $a_{a v} = \frac{6}{6} = 1 m s^{- 2}$

Q. A particle is moving eastwards with a speed of 6m/s. After 6s, the particle is found to be moving with same speed in a direction 60∘ north of east. The magnitude of average acceleration in this interval of time is

6m/s2

3m/s2

1m/s2