A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy is

Question

A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy is (A)  f/2  (B)  f  (C)  2f  (D)  4f

Tardigrade Admin · Accepted Answer

KE changes to PE from 0 to A and 0 to B. Clearly for a complete vibration, KE change in PE 2 times So, the required frequency =2× (frequency of SHM) =2f

Q. A particle is executing simple harmonic motion with frequency $f .$ The frequency at which its kinetic energy changes into potential energy is

$f /2$

$f$

$2 f$

$4 f$

$K E$ changes to $PE$ from $0$ to $A$ and $0$ to $B$ .
Clearly for a complete vibration, $K E$ change in $PE$ $2$ times
So, the required frequency $= 2 \times$ (frequency of $S H M) = 2 f$

Q. A particle is executing simple harmonic motion with frequency f. The frequency at which its kinetic energy changes into potential energy is

f/2

f

2f

4f

KE changes to PE from 0 to A and 0 to B. Clearly for a complete vibration, KE change in PE 2 times So, the required frequency =2× (frequency of SHM)=2f

Q. A particle is executing simple harmonic motion with frequency $f .$ The frequency at which its kinetic energy changes into potential energy is

$f /2$

$f$

$2 f$

$4 f$

$K E$ changes to $PE$ from $0$ to $A$ and $0$ to $B$ .
Clearly for a complete vibration, $K E$ change in $PE$ $2$ times
So, the required frequency $= 2 \times$ (frequency of $S H M) = 2 f$