Q. A particle is executing simple harmonic motion with frequency $ f. $ The frequency at which its kinetic energy changes into potential energy is
Chhattisgarh PMTChhattisgarh PMT 2004
Solution:
$KE$ changes to $PE$ from $0$ to $A$ and $0$ to $B$.
Clearly for a complete vibration, $KE$ change in $PE$ $2$ times
So, the required frequency $ =2\times $ (frequency of $SHM) =2f $
