A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to

Question

A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to (A) H (B) H 1 / 2 (C) H 0 (D) H -1 / 2

Tardigrade Admin · Accepted Answer

Velocity acquired by a particle while falling from a height H is V=√2 g H ....(i) As λ=(h/m v)=(h/m √2 g H) (Using (i)) Lambda α (1/√H)

Q. A particle is dropped from a height $H$ . The de Broglie wavelength of the particle as a function of height is proportional to

$H$

$H^{1/2}$

$H^{0}$

$H^{- 1/2}$

Velocity acquired by a particle while falling from a height $H$ is
$V = 2 g H .... (i)$
As $λ = \frac{h}{m v} = \frac{h}{m 2 g H}$ (Using (i))
$Λ α \frac{1}{H}$

Q. A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to

H

H1/2

H0

H−1/2

Velocity acquired by a particle while falling from a height H is V=2gH​....(i) As λ=mvh​=m2gH​h​ (Using (i)) ΛαH​1​

Q. A particle is dropped from a height $H$ . The de Broglie wavelength of the particle as a function of height is proportional to

$H$

$H^{1/2}$

$H^{0}$

$H^{- 1/2}$

Velocity acquired by a particle while falling from a height $H$ is
$V = 2 g H .... (i)$
As $λ = \frac{h}{m v} = \frac{h}{m 2 g H}$ (Using (i))
$Λ α \frac{1}{H}$