A particle, initially at rest on a frictionless horizontal surface, is acted upon by a horizontal force which is constant in size and direction. A graph is plotted between the work done (.W.) on the particle, against the speed of the particle (.v.) . Let there be no other horizontal forces acting on the particle. What will the graph possibly be looking like ?

Question

A particle, initially at rest on a frictionless horizontal surface, is acted upon by a horizontal force which is constant in size and direction. A graph is plotted between the work done (.W.) on the particle, against the speed of the particle (.v.) . Let there be no other horizontal forces acting on the particle. What will the graph possibly be looking like ? (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Work done = change in kinetic energy and initial kinetic energy is zero. W=(1/2)mv2 ∴ W propto v2 , graph will be parabolic in nature.

Work done = change in kinetic energy and initial kinetic energy is zero. W=21​mv2 ∴W∝v2 , graph will be parabolic in nature.

Work done $=$ change in kinetic energy and initial kinetic energy is zero.
$W = \frac{1}{2} m v^{2}$
$∴ W \propto v^{2}$ , graph will be parabolic in nature.