Q. A particle, initially at rest on a frictionless horizontal surface, is acted upon by a horizontal force which is constant in size and direction. A graph is plotted between the work done $\left(\right.W\left.\right)$ on the particle, against the speed of the particle $\left(\right.v\left.\right)$ . Let there be no other horizontal forces acting on the particle. What will the graph possibly be looking like ?
NTA AbhyasNTA Abhyas 2020
Solution:
Work done $=$ change in kinetic energy and initial kinetic energy is zero.
$W=\frac{1}{2}mv^{2}$
$\therefore W \propto v^{2}$ , graph will be parabolic in nature.
$W=\frac{1}{2}mv^{2}$
$\therefore W \propto v^{2}$ , graph will be parabolic in nature.