A particle has a displacement of 12 m towards east and 5 m towards north and finally 6 m vertically upwards. The sum of these displacement is

Question

A particle has a displacement of 12 m towards east and 5 m towards north and finally 6 m vertically upwards. The sum of these displacement is (A) 12 m (B) 10.04 m (C) 14.31m (D) None of these

Tardigrade Admin · Accepted Answer

Resultant R = S1 + S2 + S3 |R|=√(12)2+(5)2+(6)2 =√144 +25 +36 =√205 ⇒ R=14.31 cm

Q. A particle has a displacement of $12 m$ towards east and $5 m$ towards north and finally $6 m$ vertically upwards. The sum of these displacement is

12 m

10.04 m

14.31m

None of these

Resultant $R = S_{1} + S_{2} + S_{3}$
$∣ R ∣ = (12)^{2} + (5)^{2} + (6)^{2}$
$= 144 + 25 + 36 = 205 \Rightarrow R = 14.31 c m$

Q. A particle has a displacement of 12m towards east and 5m towards north and finally 6m vertically upwards. The sum of these displacement is