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  4. A particle has a displacement of 12 m towards east and 5 m towards north and finally 6 m vertically upwards. The sum of these displacement is

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Q. A particle has a displacement of $12\,m$ towards east and $5\,m$ towards north and finally $6\,m$ vertically upwards. The sum of these displacement is

Motion in a Straight Line

Solution:

Resultant $R = S_1 + S_2 + S_3$
$|R|=\sqrt{(12)^2+(5)^2+(6)^2}$
$=\sqrt{144 +25 +36 }=\sqrt{205} \Rightarrow R=14.31 cm $