Question

A particle executes simple harmonic motion. Its amplitude is $8cm$ and time period is $6s$. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ____s

Answer 1

Answer: 1

$t=\frac{\Delta \varphi }{\omega }=\frac{\pi /2-\pi /6}{2\pi /6}=\frac{\pi /3}{\pi /3}=1\sec$