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  4. A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is s

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Q. A particle executes simple harmonic motion. Its amplitude is $8\, cm$ and time period is $6 \,s$. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ____s

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Solution:

$t =\frac{\Delta \phi}{\omega}=\frac{\pi / 2-\pi / 6}{2 \pi / 6}=\frac{\pi / 3}{\pi / 3}=1 \,\sec$