A particle executes simple harmonic motion between x=-A and x=+A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then :

Question

A particle executes simple harmonic motion between x=-A and x=+A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then : (A)  T1<T2  (B)  T1>T2  (C)  T1=T2  (D)  T1=2T2

Tardigrade Admin · Accepted Answer

In SHM, velocity of particle also oscillatessimple harmonically. Speed is more near themean position and less near the extremepositions. Therefore, the time taken for the particle to go from 0 to A/ 2 will be less than the time takento go it from A/ 2 to A. Hence, T1<T2

Q. A particle executes simple harmonic motion between $x = - A$ and $x = + A .$ The time taken for it to go from 0 to A/2 is $T_{1}$ and to go from A/2 to A is $T_{2} .$ Then :

$T_{1} < T_{2}$

$T_{1} > T_{2}$

$T_{1} = T_{2}$

$T_{1} = 2 T_{2}$

In SHM, velocity of particle also oscillatessimple harmonically. Speed is more near themean position and less near the extremepositions. Therefore, the time taken for the particle to go from 0 to A/ 2 will be less than the time takento go it from A/ 2 to A. Hence, $T_{1} < T_{2}$

Q. A particle executes simple harmonic motion between x=−A and x=+A. The time taken for it to go from 0 to A/2 is T1​ and to go from A/2 to A is T2​. Then :

T1​<T2​

T1​>T2​

T1​=T2​

T1​=2T2​