Question

A particle executes simple harmonic motion between $ x=-A $ and $ x=+A. $ The time taken for it to go from 0 to A/2 is $ {{T}_{1}} $ and to go from A/2 to A is $ {{T}_{2}}. $ Then :

• A. $ {{T}_{1}}<{{T}_{2}} $
• B. $ {{T}_{1}}>{{T}_{2}} $
• C. $ {{T}_{1}}={{T}_{2}} $
• D. $ {{T}_{1}}=2{{T}_{2}} $

Answer 1

Answer: (A)

In SHM, velocity of particle also oscillatessimple harmonically. Speed is more near themean position and less near the extremepositions. Therefore, the time taken for the particle to go from 0 to A/ 2 will be less than the time takento go it from A/ 2 to A. Hence, $ {{T}_{1}}<{{T}_{2}} $