Question

A particle executes SHM with a period of $8s$ and amplitude $4cm$ . Its maximum speed in $cm/s$, is

• A. $\pi$
• B. $\frac{\pi }{2}$
• C. $\frac{\pi }{3}$
• D. $\frac{\pi }{4}$

Answer 1

Answer: (A)

For a particle executing SHM
$v_{\max }=A\omega$
$=4\times \frac{2\pi }{T}$
$=4\times \frac{2\pi }{8}=\pi cm{s}^{-1}$