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Q. A particle executes SHM with a period of $ 8\,s $ and amplitude $ 4\,cm $ . Its maximum speed in $cm/s$, is

J & K CETJ & K CET 2007Oscillations

Solution:

For a particle executing SHM
$v_{\max }=A \omega$
$=4 \times \frac{2 \pi}{T}$
$=4 \times \frac{2 \pi}{8}=\pi cm s ^{-1}$