A parallel AC circuit is shown below with R1=R2=R and XL=XC=X. An AC source is connected across the circuit as shown in the figure. The rms value of potential difference VA-VB is (V0/√n). Find n .(X=R)

Question

A parallel AC circuit is shown below with R1=R2=R and XL=XC=X. An AC source is connected across the circuit as shown in the figure. The rms value of potential difference VA-VB is (V0/√n). Find n .(X=R) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

VA=(V0 XL/√R2+X2) sin (ω t+φ) VB=(V0 XC/√R2+X2) sin (ω t-φ)

Q. A parallel AC circuit is shown below with $R_{1} = R_{2} = R$ and $X_{L} = X_{C} = X$ . An AC source is connected across the circuit as shown in the figure. The rms value of potential difference $V_{A} - V_{B}$ is $\frac{V _{0}}{n}$ . Find $n . (X = R)$

$V_{A} = \frac{V _{0} X _{L}}{R ^{2} + X ^{2}} sin (ω t + ϕ)$
$V_{B} = \frac{V _{0} X _{C}}{R ^{2} + X ^{2}} sin (ω t - ϕ)$

Q. A parallel AC circuit is shown below with R1​=R2​=R and XL​=XC​=X. An AC source is connected across the circuit as shown in the figure. The rms value of potential difference VA​−VB​ is n​V0​​. Find n.(X=R)

VA​=R2+X2​V0​XL​​sin(ωt+ϕ) VB​=R2+X2​V0​XC​​sin(ωt−ϕ)

Q. A parallel AC circuit is shown below with $R_{1} = R_{2} = R$ and $X_{L} = X_{C} = X$ . An AC source is connected across the circuit as shown in the figure. The rms value of potential difference $V_{A} - V_{B}$ is $\frac{V _{0}}{n}$ . Find $n . (X = R)$

$V_{A} = \frac{V _{0} X _{L}}{R ^{2} + X ^{2}} sin (ω t + ϕ)$
$V_{B} = \frac{V _{0} X _{C}}{R ^{2} + X ^{2}} sin (ω t - ϕ)$