A pair of adjacent coils has a mutual inductance of 1.5 H If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?

Question

A pair of adjacent coils has a mutual inductance of 1.5 H If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil? (A) 10 Wb (B) 20 Wb (C) 30 Wb (D) 40 Wb

Tardigrade Admin · Accepted Answer

ε=(MdI/dt) or (Δ φ/Δ t)=(M Δ I/Δ t) ⇒ Δ φ=M Δ I=(1.5)(20-0)=30 Wb

Q. A pair of adjacent coils has a mutual inductance of 1.5 H If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?

10 Wb

20 Wb

30 Wb

40 Wb

$ε = \frac{M d I}{d t}$ or $\frac{Δ ϕ}{Δ t} = \frac{M Δ I}{Δ t}$
$\Rightarrow Δ ϕ = M Δ I = (1.5) (20 - 0) = 30 Wb$

Q. A pair of adjacent coils has a mutual inductance of 1.5 H If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?

10 Wb

20 Wb

30 Wb

40 Wb

ε=dtMdI​ or ΔtΔϕ​=ΔtMΔI​ ⇒Δϕ=MΔI=(1.5)(20−0)=30Wb

$ε = \frac{M d I}{d t}$ or $\frac{Δ ϕ}{Δ t} = \frac{M Δ I}{Δ t}$
$\Rightarrow Δ ϕ = M Δ I = (1.5) (20 - 0) = 30 Wb$