A nucleus with mass number 240 breaks into two a fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is :

Question

A nucleus with mass number 240 breaks into two a fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is : (A) 0.9 MeV (B) 9.4 MeV (C) 804 MeV (D) 216 MeV

Tardigrade Admin · Accepted Answer

Final total binding energy =2 × 8.5 × 120 MeV =2040 MeV Initial total binding energy =240 × 7.6 MeV =1824 MeV Gain =(2040-1824) MeV =216 MeV

Q. A nucleus with mass number $240$ breaks into two a fragments each of mass number $120$ , the binding energy per nucleon of unfragmented nuclei is $7.6 M e V$ while that of fragments is $8.5 M e V$ . The total gain in the Binding Energy in the process is :

0.9 MeV

9.4 MeV

804 MeV

216 MeV

Final total binding energy
$= 2 \times 8.5 \times 120 M e V = 2040 M e V$
Initial total binding energy
$= 240 \times 7.6 M e V = 1824 M e V$
Gain $= (2040 - 1824) M e V = 216 M e V$

Q. A nucleus with mass number 240 breaks into two a fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6MeV while that of fragments is 8.5MeV. The total gain in the Binding Energy in the process is :