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Q. A nucleus with mass number $240$ breaks into two a fragments each of mass number $120$, the binding energy per nucleon of unfragmented nuclei is $7.6\, MeV$ while that of fragments is $8.5\, MeV$. The total gain in the Binding Energy in the process is :

NEETNEET 2021Nuclei

Solution:

Final total binding energy
$=2 \times 8.5 \times 120 \,MeV =2040\, MeV$
Initial total binding energy
$=240 \times 7.6\, MeV =1824\, MeV$
Gain $=(2040-1824) \,MeV =216\, MeV$