A nucleus 220 X at rest decays emitting an α-particle. If energy of daughter nucleus is 0.2 MeV , Q value of the reaction is

Question

A nucleus 220 X at rest decays emitting an α-particle. If energy of daughter nucleus is 0.2 MeV , Q value of the reaction is (A) 10.8 MeV (B) 10.9 MeV (C) 11 MeV (D) 11.1 MeV

Tardigrade Admin · Accepted Answer

Energy of daughter nucleus =0.2 MeV 0.2 MeV =(mα/mα+mD) Q 0.2 MeV =(4/220) Q (0.2 × 220/4) M e V=Q (2 × 55/10)=Q Q=11 MeV

Q. A nucleus $^{220} X$ at rest decays emitting an $α$ -particle. If energy of daughter nucleus is $0.2 M e V, Q$ value of the reaction is

10.8 MeV

10.9 MeV

11 MeV

11.1 MeV

Energy of daughter nucleus $= 0.2 M e V$
$0.2 M e V = \frac{m _{α}}{m _{α} + m _{D}} Q$
$0.2 M e V = \frac{4}{220} Q$
$\frac{0.2 \times 220}{4} M e V = Q$
$\frac{2 \times 55}{10} = Q$
$Q = 11 M e V$

Q. A nucleus 220X at rest decays emitting an α-particle. If energy of daughter nucleus is 0.2MeV,Q value of the reaction is