Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A nucleus 220 X at rest decays emitting an α-particle. If energy of daughter nucleus is 0.2 MeV , Q value of the reaction is
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. A nucleus ${ }^{220} X$ at rest decays emitting an $\alpha$-particle. If energy of daughter nucleus is $0.2\, MeV , Q$ value of the reaction is
Nuclei
A
10.8 MeV
B
10.9 MeV
C
11 MeV
D
11.1 MeV
Solution:
Energy of daughter nucleus $=0.2 \,MeV$
$0.2\, MeV =\frac{m_{\alpha}}{m_{\alpha}+m_{D}} Q $
$0.2\, MeV =\frac{4}{220} Q$
$\frac{0.2 \times 220}{4} \,M e V=Q $
$\frac{2 \times 55}{10}=Q $
$Q=11 \,MeV$