A non-ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixture will be:

Question

A non-ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixture will be: (A) > 80 ml (B) < 80 ml (C) =80 ml (D) ≥ 80 ml

Tardigrade Admin · Accepted Answer

Chloroform and acetone form a non-ideal solution in which A...B type interactions are more than

A \dots . A

and

B \dots . B

type interaction due to

H

-bonding. Hence, the solution shows negative deviation from Raoult's law

i.e.,

Δ V_{mix} = - v e; Δ H_{mix} = - v e

∴

Total volume of mixture

=< (30 + 50) m L

Q. A non-ideal solution was prepared by mixing $30 m l$ chloroform and $50 m l$ acetone. The volume of mixture will be:

> 80 ml

< 80 ml

=80 ml

$\geq 80 m l$

Q. A non-ideal solution was prepared by mixing 30ml chloroform and 50ml acetone. The volume of mixture will be:

> 80 ml

< 80 ml

=80 ml

≥80ml

Chloroform and acetone form a non-ideal solution in which A...B type interactions are more than A….A and B….B type interaction due to H -bonding. Hence, the solution shows negative deviation from Raoult's law i.e., ΔVmix ​=−ve;ΔHmix ​=−ve ∴ Total volume of mixture =<(30+50)mL

Q. A non-ideal solution was prepared by mixing $30 m l$ chloroform and $50 m l$ acetone. The volume of mixture will be:

$\geq 80 m l$