Question

A non-ideal solution was prepared by mixing $30 \,ml$ chloroform and $50\, ml$ acetone. The volume of mixture will be:

• A. > 80 ml
• B. < 80 ml
• C. =80 ml
• D. $\geq 80 ml$

Answer 1

Answer: (B)

Chloroform and acetone form a non-ideal solution in which A...B type interactions are more than $A \ldots . A$ and $B \ldots . B$ type interaction due to $H$ -bonding. Hence, the solution shows negative deviation from Raoult's law

i.e., $\Delta V _{\text {mix }}=- ve ; \Delta H _{\text {mix }}=- ve$

$\therefore $ Total volume of mixture $=<(30+50) mL$