A non-conducting ring of radius r has charge q distributed uniformly over it. If it rotates with an angular velocity ω, then the equivalent current is

Question

A non-conducting ring of radius r has charge q distributed uniformly over it. If it rotates with an angular velocity ω, then the equivalent current is (A) (q ω /2 π ) (B) (2 π /q ω ) (C) (q ω /2 π r) (D) qrω

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-pk8nglig1lhi.png" /> Non conducting charge ring rotates with an angular velocity Ï is equivalent to electric current I=(q/T) = (q v/2 π r) = (q r ω /2 π r)=(q ω /2 π )

Q. A non-conducting ring of radius $r$ has charge $q$ distributed uniformly over it. If it rotates with an angular velocity $ω,$ then the equivalent current is

$\frac{q ω}{2 π}$

$\frac{2 π}{q ω}$

$\frac{q ω}{2 π r}$

$q r ω$

Non conducting charge ring rotates with an angular velocity ω is equivalent to electric current
$I = \frac{q}{T}$ = $\frac{q v}{2 π r}$ = $\frac{q r ω}{2 π r} = \frac{q ω}{2 π}$

Q. A non-conducting ring of radius r has charge q distributed uniformly over it. If it rotates with an angular velocity ω, then the equivalent current is

2πqω​

qω2π​

2πrqω​

qrω