Question

A non-conducting ring of radius $r$ has charge $q$ distributed uniformly over it. If it rotates with an angular velocity $ω, \, $ then the equivalent current is

• A. $\frac{q \omega }{2 \pi }$
• B. $\frac{2 \pi }{q \omega }$
• C. $\frac{q \omega }{2 \pi r}$
• D. $qr\omega $

Answer 1

Answer: (A)

Non conducting charge ring rotates with an angular velocity ω is equivalent to electric current
$I=\frac{q}{T}$ = $\frac{q v}{2 \pi r}$ = $\frac{q r \omega }{2 \pi r}=\frac{q \omega }{2 \pi }$