A neutral compound with molecular formula C3H8O evolves H2 when treated with sodium metal and gives iodoform test. The compound is

Question

A neutral compound with molecular formula C3H8O evolves H2 when treated with sodium metal and gives iodoform test. The compound is (A)  (CH3)2CHOH  (B)  CH3CH2CH2OH  (C)  CH3COCH3  (D)  CH3CH2CHO

Tardigrade Admin · Accepted Answer

Since, the compound evolves H 2 on treatment with Na metal, it must contain an OH group. Further, since it gives iodoform test, therefore, it must contain the grouping CH 3 CHOH - or CH 3 CO -. Both these reactions are given by compound ( CH 3)2 CHOH or CH 3 CHOHCH 3.

Q. A neutral compound with molecular formula $C_{3} H_{8} O$ evolves $H_{2}$ when treated with sodium metal and gives iodoform test. The compound is

$(C H_{3})_{2} C H O H$

$C H_{3} C H_{2} C H_{2} O H$

$C H_{3} COC H_{3}$

$C H_{3} C H_{2} C H O$

Q. A neutral compound with molecular formula C3​H8​O evolves H2​ when treated with sodium metal and gives iodoform test. The compound is

(CH3​)2​CHOH

CH3​CH2​CH2​OH

CH3​COCH3​

CH3​CH2​CHO

Since, the compound evolves H2​ on treatment with Na metal, it must contain an OH group. Further, since it gives iodoform test, therefore, it must contain the grouping CH3​CHOH− or CH3​CO−. Both these reactions are given by compound (CH3​)2​CHOH or CH3​CHOHCH3​.

Q. A neutral compound with molecular formula $C_{3} H_{8} O$ evolves $H_{2}$ when treated with sodium metal and gives iodoform test. The compound is

$(C H_{3})_{2} C H O H$

$C H_{3} C H_{2} C H_{2} O H$

$C H_{3} COC H_{3}$

$C H_{3} C H_{2} C H O$