A moving coil galvanometer has a resistance of 900 Ω. In order to send only 10 % of the main current through this galvanometer, the resistance of the required shunt is

Question

A moving coil galvanometer has a resistance of 900 Ω. In order to send only 10 % of the main current through this galvanometer, the resistance of the required shunt is (A) 0.9 Ω (B) 100 Ω (C) 405 Ω (D) 90 Ω

Tardigrade Admin · Accepted Answer

I8=0.1 I, Is=0.9 I ; S=I3 G / Is =0.1 × 900 / 0.9=100 Ω

Q. A moving coil galvanometer has a resistance of $900 Ω$ . In order to send only $10%$ of the main current through this galvanometer, the resistance of the required shunt is

$0.9 Ω$

$100 Ω$

$405 Ω$

$90 Ω$

$I_{8} = 0.1 I, I_{s} = 0.9 I; S = I_{3} G / I_{s}$
$= 0.1 \times 900/0.9 = 100Ω$

Q. A moving coil galvanometer has a resistance of 900Ω. In order to send only 10% of the main current through this galvanometer, the resistance of the required shunt is

0.9Ω

100Ω

405Ω

90Ω