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Q. A moving coil galvanometer has a resistance of $900\, \Omega$. In order to send only $10 \%$ of the main current through this galvanometer, the resistance of the required shunt is

AIIMSAIIMS 2009Moving Charges and Magnetism

Solution:

$I_{8}=0.1 \,I, I_{s}=0.9 I ; S=I_{3} G / I_{s}$
$=0.1 \times 900 / 0.9=100 \Omega$