A mosquito with 8 legs stands on water surface and each leg makes depression of radius a . If the surface tension and angle of contact are T and zero respectively ,then the weight of mosquito is

Question

A mosquito with 8 legs stands on water surface and each leg makes depression of radius a . If the surface tension and angle of contact are T and zero respectively ,then the weight of mosquito is (A) 8 Ta (B) 16π Ta (C) (T a/8) (D) (T a/16 π )

Tardigrade Admin · Accepted Answer

Figure shows one of the legs of the mosquito landing upon the water surface. Therefore, T.2π a× 8=W= weight of the mosquito. T.16π a=W

Q. A mosquito with $8$ legs stands on water surface and each leg makes depression of radius $a$ . If the surface tension and angle of contact are $T$ and zero respectively ,then the weight of mosquito is

$8 T a$

$16 π T a$

$\frac{T a}{8}$

$\frac{T a}{16 π}$

Figure shows one of the legs of the mosquito landing upon the water surface.
Therefore, $T .2 πa \times 8 = W =$ weight of the mosquito.
$T .16 πa = W$

Q. A mosquito with 8 legs stands on water surface and each leg makes depression of radius a . If the surface tension and angle of contact are T and zero respectively ,then the weight of mosquito is

8Ta

16πTa

8Ta​

16πTa​