Question

A mosquito with $8$ legs stands on water surface and each leg makes depression of radius $a$ . If the surface tension and angle of contact are $T$ and zero respectively ,then the weight of mosquito is

• A. $8 \, Ta$
• B. $16\pi Ta$
• C. $\frac{T a}{8}$
• D. $\frac{T a}{16 \pi }$

Answer 1

Answer: (B)

Figure shows one of the legs of the mosquito landing upon the water surface.
Therefore, $T.2\pi a\times 8=W=$ weight of the mosquito.
$T.16\pi a=W$