A monoatomic gas is kept at room temperature 300 K . Calculate the average kinetic energy of gas molecule (Use k = 1.38 × 10-23 MKS units)

Question

A monoatomic gas is kept at room temperature 300 K . Calculate the average kinetic energy of gas molecule (Use k = 1.38 × 10-23 MKS units) (A)  0.138 eV  (B)  0.062 eV  (C)  0.039 eV  (D)  0.013 eV

Tardigrade Admin · Accepted Answer

Average kinetic energy of gas molecules =(3/2)× KB× T KEav=(3/2)× 1.38×10-23× 300 =6.21× 10-21 =(6.21× 10-21 eV/1.6 × 10-19) =3.8× 10-2 =0.038 eV

Q. A monoatomic gas is kept at room temperature $300 K$ . Calculate the average kinetic energy of gas molecule (Use $k = 1.38 \times 1 0^{- 23} M K S$ units)

$0.138 e V$

$0.062 e V$

$0.039 e V$

$0.013 e V$

Average kinetic energy of gas molecules
$= \frac{3}{2} \times K_{B} \times T$
$K E_{a v} = \frac{3}{2} \times 1.38 \times 1 0^{- 23} \times 300$
$= 6.21 \times 1 0^{- 21}$
$= \frac{6.21 \times 1 0 ^{- 21 e V}}{1.6 \times 1 0 ^{- 19}}$
$= 3.8 \times 1 0^{- 2}$
$= 0.038 e V$

Q. A monoatomic gas is kept at room temperature 300K . Calculate the average kinetic energy of gas molecule (Use k=1.38×10−23MKS units)

0.138eV

0.062eV

0.039eV

0.013eV