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Q.
A monoatomic gas is kept at room temperature $ 300\,K $ . Calculate the average kinetic energy of gas molecule (Use $ k = 1.38 \times 10^{-23}\,MKS $ units)
AMUAMU 2010Kinetic Theory
Solution:
Average kinetic energy of gas molecules
$=\frac{3}{2}\times K_{B}\times T$
$KE_{av}=\frac{3}{2}\times 1.38\times10^{-23}\times 300$
$=6.21\times 10^{-21}$
$=\frac{6.21\times 10^{-21\,eV}}{1.6 \times 10^{-19}}$
$=3.8\times 10^{-2}$
$=0.038\,eV$