A mono-basic weak acid solution has a molarity of 0.005 M and pH of 5 . What this percentage ionisation in this solution?

Question

A mono-basic weak acid solution has a molarity of 0.005 M and pH of 5 . What this percentage ionisation in this solution? (A) 2.0 (B) 0.2 (C) 0.5 (D) 20.0

Tardigrade Admin · Accepted Answer

C α=[ H +] α=(10-5/5 × 10-3)=(1/5) × 10-2 % ionisation =(1/5) × 10-2 × 100=0.2 %

Q. A mono-basic weak acid solution has a molarity of 0.005 $M$ and $p H$ of $5.$ What this percentage ionisation in this solution?

2.0

0.2

0.5

20.0

$C α = [H^{+}]$

$α = \frac{1 0 ^{- 5}}{5 \times 1 0 ^{- 3}} = \frac{1}{5} \times 1 0^{- 2}$

$%$ ionisation $= \frac{1}{5} \times 1 0^{- 2} \times 100 = 0.2%$

Q. A mono-basic weak acid solution has a molarity of 0.005 M and pH of 5. What this percentage ionisation in this solution?

2.0

0.2

0.5

20.0

Cα=[H+] α=5×10−310−5​=51​×10−2 % ionisation =51​×10−2×100=0.2%

Q. A mono-basic weak acid solution has a molarity of 0.005 $M$ and $p H$ of $5.$ What this percentage ionisation in this solution?

$C α = [H^{+}]$

$α = \frac{1 0 ^{- 5}}{5 \times 1 0 ^{- 3}} = \frac{1}{5} \times 1 0^{- 2}$

$%$ ionisation $= \frac{1}{5} \times 1 0^{- 2} \times 100 = 0.2%$