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Q. A mono-basic weak acid solution has a molarity of 0.005 $M$ and $pH$ of $5 .$ What this percentage ionisation in this solution?

Equilibrium

Solution:

$C \alpha=\left[ H ^{+}\right]$

$\alpha=\frac{10^{-5}}{5 \times 10^{-3}}=\frac{1}{5} \times 10^{-2}$

$\%$ ionisation $=\frac{1}{5} \times 10^{-2} \times 100=0.2 \%$