Question

A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is

• A. $\frac{R}{2}$
• B. R
• C. $\frac{3R}{2}$
• D. 2R
• E. 3 R

Answer 1

Answer: (E)

We know that,
Specific heat of a gas (At constant volume)
$C_V=\frac{f}{2}\times R$
where $R=$ number of independent relations
$f=$ degree of freedom
$=\frac{6}{2}\times R=3R$