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Q. A molecule of a gas has six degrees of freedom. Then the molar specific heat of the gas at constant volume is

KEAMKEAM 2014Kinetic Theory

Solution:

We know that,
Specific heat of a gas (At constant volume)
$C_{V}=\frac{f}{2} \times R$
where $R=$ number of independent relations
$f=$ degree of freedom
$=\frac{6}{2} \times R=3 \,R$