A mixture of hydrogen and oxygen has volume 2000 cm 3, temperature 300 K, pressure 100 kPa and mass 0.76 g The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

Question

A mixture of hydrogen and oxygen has volume 2000 cm 3, temperature 300 K, pressure 100 kPa and mass 0.76 g The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be : (A) (1/3) (B) (3/1) (C) (1/16) (D) (16/1)

Tardigrade Admin · Accepted Answer

PV = nRT n=(100 × 103 × 2000 × 10-6/(25)3 × 300) n=80 × 10-3 n1+n2=0.08 n1 × 2+n2 × 32=0.76 (0.08-n2) 2+n2(32)=0.76 n2=0.02 n1=0.06 (n1/n2)=(3/1)

Q. A mixture of hydrogen and oxygen has volume $2000 c m^{3}$ , temperature $300 K$ , pressure $100 k P a$ and mass $0.76 g$ The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

$\frac{1}{3}$

$\frac{3}{1}$

$\frac{1}{16}$

$\frac{16}{1}$

$P V = n RT$
$n = \frac{100 \times 1 0 ^{3} \times 2000 \times 1 0 ^{- 6}}{\frac{25}{3} \times 300}$
$n = 80 \times 1 0^{- 3}$
$n_{1} + n_{2} = 0.08$
$n_{1} \times 2 + n_{2} \times 32 = 0.76$
$(0.08 - n_{2}) 2 + n_{2} (32) = 0.76$
$n_{2} = 0.02$
$n_{1} = 0.06$
$\frac{n _{1}}{n _{2}} = \frac{3}{1}$

Q. A mixture of hydrogen and oxygen has volume 2000cm3, temperature 300K, pressure 100kPa and mass 0.76g The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be :

31​

13​

161​

116​