A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K. The vapour pressure of propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be

Question

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K. The vapour pressure of propyl alcohol is 200 mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be (A) 350 (B) 300 (C) 700 (D) 360

Tardigrade Admin · Accepted Answer

Let the vapour pressure of pure ethyl alcohol be P, According to Raoultâs law P=(290-80/0.6)=350 mm Hg

Q. A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290 mm$ at $300 K$ . The vapour pressure of propyl alcohol is $200 mm$ . If the mole fraction of ethyl alcohol is $0.6$ , its vapour pressure (in mm) at the same temperature will be

$350$

$300$

$700$

$360$

Let the vapour pressure of pure ethyl alcohol be P, According to Raoult’s law
$P = \frac{290 - 80}{0.6} = 350 mm H g$

Q. A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290mm at 300K. The vapour pressure of propyl alcohol is 200mm. If the mole fraction of ethyl alcohol is 0.6, its vapour pressure (in mm) at the same temperature will be

350

300

700

360